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[Relativity] Relativistic Energy-Momentum Relation

2021-09-11 15:37 作者:AoiSTZ23  | 我要投稿

By: Tao Steven Zheng (鄭濤)


【Problem】

Begin with the relativistic momentum and energy:

p%3D%20%5Cfrac%7Bmv%7D%7B%5Csqrt%7B1-%5Cfrac%7Bv%5E2%7D%7Bc%5E2%7D%7D%7D

E%3D%5Cfrac%7Bmc%5E2%7D%7B%5Csqrt%7B1-%5Cfrac%7Bv%5E2%7D%7Bc%5E2%7D%7D%7D

Derive the relativistic energy-momentum relation:

E%5E2%3D(pc)%5E2%2B(mc%5E2)%5E2


【Solution】


With a little algebra we discover that

%5Cfrac%7Bp%7D%7BE%7D%3D%5Cfrac%7Bv%7D%7Bc%5E2%7D

Square the equation for relativistic energy

E%5E2%3D%5Cfrac%7B(mc%5E2)%5E2%7D%7B1-%5Cfrac%7Bv%5E2%7D%7Bc%5E2%7D%7D

And rearrange to arrive at

E%5E2-%5Cfrac%7BE%5E2%20v%5E2%7D%7Bc%5E2%7D%20%3D(mc%5E2)%5E2

E%5E2%3D%5Cfrac%7BE%5E2%20v%5E2%7D%7Bc%5E2%7D%20%2B(mc%5E2%20)%5E2%20

From the relation

%5Cfrac%7Bp%7D%7BE%7D%3D%5Cfrac%7Bv%7D%7Bc%5E2%7D

we find

%5Cfrac%7Bp%7D%7BE%7D%3D%5Cfrac%7Bv%7D%7Bc%5E2%7D

and

(pc)%5E2%3D%5Cfrac%7BE%5E2%20v%5E2%7D%7Bc%5E2%7D

Substitute this result into

E%5E2%3D%5Cfrac%7BE%5E2%20v%5E2%7D%7Bc%5E2%7D%20%2B(mc%5E2)%5E2

to get

E%5E2%3D(pc)%5E2%2B(mc%5E2)%5E2


Note: When the momentum of an object is zero, the expression reduces to Einstien's famous mass-energy equivalence principle E%3Dmc%5E2.



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