Can you solve the giant cat army riddle

你能解決巨貓軍之謎嗎

來(lái)源視頻

The villainous Dr. Schr?dinger has developed a growth ray and intends to create an army of giant cats to terrorize the city.?

Your team of secret agents has tracked him to his underground lab.?

You burst in to find… that it’s a trap!

Dr. Schr?dinger has slipped into the next room to activate his device and disabled the control panel on the way out.

邪惡博士薛定諤?發(fā)明了一種生長(zhǎng)射線，他意圖制造一支巨貓軍隊(duì)，造成市民恐慌。

你所在的秘密特工小隊(duì)跟蹤薛定諤博士?來(lái)到他的地下實(shí)驗(yàn)室。

你們經(jīng)過(guò)深入調(diào)查，?卻發(fā)現(xiàn)這是個(gè)陷阱！

薛定諤博士已經(jīng)到隔壁房間?激活了他的裝置，他破壞了撤出路線的控制板。

Fortunately, your teammates are masters of spy-craft. Agent Delta has hacked into the control panel and managed to reactivate some of its functionality.?

Meanwhile, Agent Epsilon has searched through surveillance to find the code for the door: 2, 10, 14. All you have to do is enter those numbers and you’ll be free.

But there’s a problem.?

The control panel has only three buttons: one which adds 5 to the display number, one which adds 7, and one which takes the square root.?

You need to make the display output the numbers 2, 10, and 14, in that order.

It’s okay if it outputs different numbers in between, but there’s no way to reset the display, so once you get to 2, you’ll have to continue on to 10 and 14 from there.

幸運(yùn)的是，?你的團(tuán)隊(duì)成員都是間諜大師。德?tīng)査毓ず谌肓丝刂泼姘?，成功激活了部分功能?/p>

與此同時(shí)，艾普西龍?zhí)毓?查看了監(jiān)控錄像，發(fā)現(xiàn)了開(kāi)門的密碼：2?，10?，和?14?。你只需要輸入這些數(shù)字 就可以獲得自由。

但還有一個(gè)問(wèn)題?？刂泼姘逯挥腥齻€(gè)按鍵，一個(gè)是給顯示屏上的數(shù)字加?5?，另一個(gè)是加?7?，最后一個(gè)則是開(kāi)平方。

你需要讓顯示器按順序出現(xiàn)2?，10?，14?這三個(gè)數(shù)字。

在兩個(gè)目標(biāo)數(shù)字之間 可以出現(xiàn)其他數(shù)字，但是無(wú)法重置輸入過(guò)程，因此，一旦你得到了?2，你需要在此基礎(chǔ)上繼續(xù)輸入 直到得到?10?和?14?。

Not only that, Agent Delta explains that there are other traps built into the panel.

If it ever shows the same number more than once, a number greater than 60, or a non-whole number, the room will explode.

Right now, the display reads zero, and time is running out.?

There’s only one way to solve the puzzle, with a few small variations.?

How will you input the code to escape from Dr. Schr?dinger’s lair and save the day??

Pause the video now if you want to figure it out for yourself!?

Answer in: 3 2 1.

德?tīng)査毓ふf(shuō)規(guī)則不僅如此，控制面板中還設(shè)置了其他陷阱。

如果重復(fù)出現(xiàn)了同樣的數(shù)字，或是數(shù)字大于?60，再或者出現(xiàn)了非整數(shù)，這個(gè)房間就都會(huì)爆炸。

現(xiàn)在，顯示屏上的數(shù)字是?0?而時(shí)間所剩無(wú)幾。

這道題目的解答方法 只有一種且變化很少。

為了逃離薛定諤博士的實(shí)驗(yàn)室 并拯救城市，你將如何輸入密碼？

如果你想自己解題，請(qǐng)?jiān)诖藭和！?/p>

離答案揭曉還有：3?秒，2?秒，1?秒。

You look over your options.

Adding 5 or 7 increases the number, and the square root button will make it smaller.

But there are only a few options where you can use that button: 4 9 16 25, 36, and 49.?

You’d love to make 4 or 16.?

Then you could hit the square root button once or twice to get 2.?

But you can’t make either with just the 5 and 7 buttons.?

What will you do??

You look at the other possible options for numbers you could take the square root of.

Nine you can’t reach.?

Twenty-five and 49 would take you back to 5 or 7, and you can already get to each of those.

Thirty-six is your only option.?

You add 5, 7, 5, 7, 5, 7, and then hit the square root button.

你思考著對(duì)策。

加?5?或加?7?會(huì)讓數(shù)字增加，而平方根會(huì)讓數(shù)字變小。

但使用平方根的機(jī)會(huì)很少，只有?4，9，16，25，36，49。

你希望能得到?4?或是?16?。

然后開(kāi)一次或兩次根號(hào) 就可以得到?2。

但這兩個(gè)數(shù)字都沒(méi)辦法 用加?5?和加?7?獲得。

這該如何是好?

你嘗試想出其他的對(duì)策 得出可以開(kāi)方的數(shù)字。

9?是無(wú)法得出的。

25?和?49?會(huì)讓 你得到?5?和?7?，但你本來(lái)就可以得到這兩個(gè)數(shù)字。

36?成了你唯一的選擇。

你先加?5，再加?7，再加?5，再加?7，再加?5，再加?7，然后敲下開(kāi)平方的按鍵。

Why that series of 5s and 7s??

It’s somewhat arbitrary, but you know that you want to avoid 10, 14, and perfect squares, since you’ll need them later.?

This gets you to 6.?

Does that help??

Looking at your options, you see that 16 is now in your sights.?

You add 5 twice more to reach it.?

Then hit square root twice.?

That gets you to 2.?

You’re on your way!?

Now to 10.?

You can’t get straight there through addition alone, so you’re going to have to reach another square.?

Taking the square root of 9 or 25 would get you to a good place, but it turns out that 25 is unreachable from 2.?

So you add 7 to get to 9, then take the square root again.?

That gets you to 3. Adding 7 again makes 10.?

Finally, you need to reach 14.

為什么以這個(gè)順序加?5?和加?7?呢？

看上去是隨機(jī)的，但是你需要避開(kāi)?10，14?和完全平方數(shù)，畢竟你之后還要用到它們。

這下你得到了?6。這有用么？

再思考一下，你發(fā)現(xiàn)?16?這個(gè)數(shù)字變得唾手可得。

通過(guò)兩次加?5?就可以得到。

然后開(kāi)平方兩次。

就得到了?2。

進(jìn)展不錯(cuò)！

下一個(gè)目標(biāo)數(shù)字是?10。

你無(wú)法通過(guò)加法直接得到這個(gè)數(shù)字，因此你還是要 先得到某個(gè)完全平方數(shù)。

對(duì)?9?和?25?開(kāi)根號(hào) 會(huì)帶來(lái)不錯(cuò)的結(jié)果，但是無(wú)法從?2?得到?25?。

所以你在?2?的基礎(chǔ)上 加?7?得到?9，然后開(kāi)根號(hào)。

這就得到了?3。再加?7?得到?10。

最后的目標(biāo)數(shù)字是?14。

Thinking backwards, you imagine where you could be before 14: 7 or 9.?

But 9 won’t work because you’ve already used 9.?

However, you could get to 7 by reaching 49 first.?

You add your way towards it, being careful not to hit any of the numbers you’ve hit so far.

You thread your way carefully, adding five 5s and two 7s.?

Then, square root to 7, and add 7 more.

The door opens, and you’re out of the trap.

通過(guò)逆向思考，設(shè)想在?14?之前 可以得到的數(shù)字有哪些？7?或是?9。

但是不能選?9， 因?yàn)?9?已經(jīng)出現(xiàn)過(guò)一次。

但是你可以通過(guò) 對(duì)?49?開(kāi)根號(hào)得到?7。

你通過(guò)加法試圖得到?49，要小心不重復(fù)之前出現(xiàn)過(guò)的數(shù)字。

你小心翼翼，加上?5?個(gè)?5?和?2?個(gè)?7。

然后開(kāi)根號(hào)得到?7， 再加?7。

門開(kāi)了，你們成功脫困。

Thanks to your problem-solving skills, your team gets Schr?dinger’s cats out of the box in the nick of time.?

As for Schr?dinger, you can be certain of one thing: he’ll be spending quite some time in a box of his own.

由于你出色的問(wèn)題解決能力，你的小隊(duì)在最后一刻 抓到了薛定諤的貓。

至于薛定諤，你可以確定的是，他要在自己的盒子里 待上好一段時(shí)間了。