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Leetcode1389. Create Target Array in the Given Order

2023-01-02 12:52 作者:您是打尖兒還是住店呢  | 我要投稿

Given two arrays of integers?nums?and?index. Your task is to create?target?array under the following rules:

  • Initially?target?array is empty.

  • From left to right read nums[i] and index[i], insert at index?index[i]?the value?nums[i]?in?target?array.

  • Repeat the previous step until there are no elements to read in?nums?and?index.

Return the?target?array.

It is guaranteed that the insertion operations will be valid.

?

Example 1:

Input: nums = [0,1,2,3,4], index = [0,1,2,2,1]Output: [0,4,1,3,2]

Explanation:

nums? ? ? ?index? ? ?target

0????????????????0????????????[0]

1? ? ? ? ? ? ???1? ? ? ? ? ???[0,1]?

2? ? ? ? ? ? ???2? ? ? ? ? ?? [0,1,2]?

3? ? ? ? ? ? ????2 ? ? ? ? ? ?[0,1,3,2]

4 ? ? ? ? ? ? ? ?1 ? ? ? ?? ? ?[0,4,1,3,2]

Example 2:

Input: nums = [1,2,3,4,0], index = [0,1,2,3,0]Output: [0,1,2,3,4]

Explanation:

nums ? ? ? index ? ? target?

1? ? ? ? ? ? ? ? 0? ? ? ? ? ??[1]?

2? ? ?? ? ? ? ? ?1? ? ?? ? ? ?[1,2]

3? ?? ? ? ? ? ? ?2? ? ??? ? ? ?[1,2,3]?

4? ?? ? ? ? ? ? ?3? ? ? ? ???? [1,2,3,4]

0? ?? ? ? ? ? ? ?0? ? ? ? ? ? ?[0,1,2,3,4]


Example 3:

Input: nums = [1], index = [0]

Output: [1]

?

Constraints:

  • 1 <= nums.length, index.length <= 100

  • nums.length == index.length

  • 0 <= nums[i] <= 100

  • 0 <= index[i] <= i

    ArrayList 可以直接insert 在第i個(gè)位置插入一個(gè)值,所以直接一次循環(huán),然后再放入數(shù)組中即可。就是用ArrayList的特性;

Runtime0 ms

Beats

100%

Memory40.6 MB

Beats

91.4%


Leetcode1389. Create Target Array in the Given Order的評(píng)論 (共 條)

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