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面積分割術(shù)(2019課標Ⅲ圓錐曲線)

2022-08-23 20:33 作者:數(shù)學老頑童  | 我要投稿

(2019課標Ⅲ,21)已知曲線Cy%3D%5Cfrac%7Bx%5E2%7D%7B2%7D,D為直線y%3D-%5Cfrac%7B1%7D%7B2%7D上的動點,過DC的兩條切線,切點分別為A、B.

(1)證明:直線AB過定點;

(2)若以E%5Cleft(%200%2C%5Cfrac%7B5%7D%7B2%7D%20%5Cright)%20為圓心的圓與直線AB相切,且切點為線段AB的中點,求四邊形ADBE的面積.

解:(1)先畫個圖

設(shè)點A、BD的坐標分別為

%5Cleft(%20x_1%2Cy_1%20%5Cright)%20、B%5Cleft(%20x_2%2Cy_2%20%5Cright)%20、D%5Cleft(%20k%2C-%5Cfrac%7B1%7D%7B2%7D%20%5Cright)%20,

求導,得y'%3Dx,

故點A處的切線斜率為x_1,

故點A處的切線方程為

y-y_1%3Dx_1%5Cleft(%20x-x_1%20%5Cright)%20,

因該切線過點D,

-%5Cfrac%7B1%7D%7B2%7D-y_1%3Dx_1%5Cleft(%20k-x_1%20%5Cright)%20,

-%5Cfrac%7B1%7D%7B2%7D-y_1%3Dkx_1-x_%7B1%7D%5E%7B2%7D,

-%5Cfrac%7B1%7D%7B2%7D-y_1%3Dkx_1-2y_1,

%5Ccolor%7Bred%7D%7By_1%7D%3Dk%5Ccolor%7Bred%7D%7Bx_1%7D%2B%5Cfrac%7B1%7D%7B2%7D%20,

同理可得%5Ccolor%7Bred%7D%7By_2%7D%3Dk%5Ccolor%7Bred%7D%7Bx_2%7D%2B%5Cfrac%7B1%7D%7B2%7D%20,

可知點A%5Cleft(%20x_1%2Cy_1%20%5Cright)%20B%5Cleft(%20x_2%2Cy_2%20%5Cright)%20皆在直線

%5Ccolor%7Bred%7D%7By%7D%3Dk%5Ccolor%7Bred%7D%7Bx%7D%2B%5Cfrac%7B1%7D%7B2%7D%20上,

所以直線AB的方程即為

%5Ccolor%7Bred%7D%7By%7D%3Dk%5Ccolor%7Bred%7D%7Bx%7D%2B%5Cfrac%7B1%7D%7B2%7D%20.

易知其過定點F%5Cleft(%200%2C%5Cfrac%7B1%7D%7B2%7D%20%5Cright)%20.

(2)設(shè)線段AB的中點為M%5Cleft(%20x_0%2Cy_0%20%5Cright)%20,

聯(lián)立曲線C與直線AB,得

x%5E2-2kx-1%3D0,

所以x_1%2Bx_2%3D2kx_1x_2%3D-1,

所以x_0%3D%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%3Dk,

所以y_0%3Dk%5E2%2B%5Cfrac%7B1%7D%7B2%7D

所以M的坐標為%5Cleft(%20k%2Ck%5E2%2B%5Cfrac%7B1%7D%7B2%7D%20%5Cright)%20.

%5Cbigtriangleup%20EAB鉛垂高%5Cleft%7C%20EF%20%5Cright%7C%3D2,

%5Cbigtriangleup%20DAB鉛垂高

%5Cleft%7C%20MD%20%5Cright%7C%3Dk%5E2%2B%5Cfrac%7B1%7D%7B2%7D-%5Cleft(%20-%5Cfrac%7B1%7D%7B2%7D%20%5Cright)%20%3Dk%5E2%2B1

而它們共同的水平寬

%5Cbegin%7Baligned%7D%0A%09%5Cleft%7C%20x_1-x_2%20%5Cright%7C%26%3D%5Csqrt%7B%5Cleft(%20x_1%2Bx_2%20%5Cright)%20%5E2-4x_1x_2%7D%5C%5C%0A%09%26%3D%5Csqrt%7B%5Cleft(%202k%20%5Cright)%20%5E2-4%5Ctimes%20%5Cleft(%20-1%20%5Cright)%7D%5C%5C%0A%09%26%3D2%5Csqrt%7Bk%5E2%2B1%7D%5C%5C%0A%5Cend%7Baligned%7D

所以

%5Cbegin%7Baligned%7D%0A%09S_%7B%5Ctext%7B%E5%9B%9B%E8%BE%B9%E5%BD%A2%7DADBE%7D%26%3DS_%7B%5Cbigtriangleup%20EAB%7D%2BS_%7B%5Cbigtriangleup%20DAB%7D%5C%5C%0A%09%26%3D%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5Cleft%7C%20x_1-x_2%20%5Cright%7C%5Ccdot%20%5Cleft%7C%20EF%20%5Cright%7C%2B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5Cleft%7C%20x_1-x_2%20%5Cright%7C%5Ccdot%20%5Cleft%7C%20MD%20%5Cright%7C%5C%5C%0A%09%26%3D%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5Cleft%7C%20x_1-x_2%20%5Cright%7C%5Ccdot%20%5Cleft(%20%5Cleft%7C%20EF%20%5Cright%7C%2B%5Cleft%7C%20MD%20%5Cright%7C%20%5Cright)%5C%5C%0A%09%26%3D%5Cfrac%7B1%7D%7B2%7D%5Ccdot%202%5Csqrt%7Bk%5E2%2B1%7D%5Ccdot%20%5Cleft(%202%2Bk%5E2%2B1%20%5Cright)%5C%5C%0A%09%26%3D%5Cleft(%20k%5E2%2B3%20%5Cright)%20%5Csqrt%7Bk%5E2%2B1%7D%5C%5C%0A%5Cend%7Baligned%7D

%5Coverrightarrow%7BFM%7D%3D%5Cleft(%20k%2Ck%5E2%20%5Cright)%20,%5Coverrightarrow%7BEM%7D%3D%5Cleft(%20k%2Ck%5E2-2%20%5Cright)%20,

由題可知%5Coverrightarrow%7BFM%7D%5Cbot%20%5Coverrightarrow%7BEM%7D,

k%5Ccdot%20k%2Bk%5E2%5Ccdot%20%5Cleft(%20k%5E2-2%20%5Cright)%20%3D0,

解得k%5E2%3D0,或k%5E2%3D1,

k%5E2%3D0時,S_%7B%5Ctext%7B%E5%9B%9B%E8%BE%B9%E5%BD%A2%7DADBE%7D%3D3,如圖:

k%5E2%3D1時,S_%7B%5Ctext%7B%E5%9B%9B%E8%BE%B9%E5%BD%A2%7DADBE%7D%3D4%5Csqrt%7B2%7D,如圖:


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