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LeetCode 1566. Detect Pattern of Length M Repeated K or More Tim

2023-05-11 12:24 作者:您是打尖兒還是住店呢  | 我要投稿

Given an array of positive integers?arr, find a pattern of length?m?that is repeated?k?or more times.

A?pattern?is a subarray (consecutive sub-sequence) that consists of one or more values, repeated multiple times?consecutively?without overlapping. A pattern is defined by its length and the number of repetitions.

Return?true?if there exists a pattern of length?m?that is repeated?k?or more times, otherwise return?false.

?

Example 1:

Input: arr = [1,2,4,4,4,4], m = 1, k = 3

Output: true

Explanation: The pattern (4) of length 1 is repeated 4 consecutive times. Notice that pattern can be repeated k or more times but not less.

Example 2:

Input: arr = [1,2,1,2,1,1,1,3], m = 2, k = 2

Output: true

Explanation: The pattern (1,2) of length 2 is repeated 2 consecutive times. Another valid pattern (2,1) is also repeated 2 times.

Example 3:

Input: arr = [1,2,1,2,1,3], m = 2, k = 3

Output: false

Explanation: The pattern (1,2) is of length 2 but is repeated only 2 times. There is no pattern of length 2 that is repeated 3 or more times.

?

Constraints:

  • 2 <= arr.length <= 100

  • 1 <= arr[i] <= 100

  • 1 <= m <= 100

  • 2 <= k <= 100

主要就是理解題意,連續(xù)重復(fù)的數(shù)量,

依次遍歷累加就行了。

下面是代碼;

Runtime:?0 ms, faster than?100.00%?of?Java?online submissions for?Detect Pattern of Length M Repeated K or More Times.

Memory Usage:?40.7 MB, less than?30.71%?of?Java?online submissions for?Detect Pattern of Length M Repeated K or More Times.


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